Linux / Unix sed: Delete Word From File / Input

I‘ve a file as follows:

This is a test.
One bang two three
Foo dang Bar
001 0xfg 0xA
002 0xA foo bar 0xfG
I'm done

How do I delete all “words” from the above file which ends with a particular letter (say ‘g’) in each line? The output should be as follows:

This is a test.
One two three
Foo Bar
001 0xA
002 0xA foo bar
I'm done

How do I delete regex-based word using sed or awk under Linux / Unix like operating systems?

You can use any standard Unix text editing and processing utility to find and replace/delete words from the file.

Sed example

The syntax is:

sed 's/<word>//g' input
sed -e 's/<regex-for-word>//g' input > output

In this example, delete foo word from input:

echo 'This is a foo test' | sed -e 's/<foo>//g'

To delete all words ending with a letter ‘g’ in each line, enter:

sed -e 's/<[a-zA-Z0-9]*[g|G]>//g' input

Awk example

The syntax is:

awk '{gsub("word", "");print}' input
awk '{gsub("regex", "");print}' input > output

In this example, delete bar word from input:

awk '{gsub("bar", "");print}' <<< "This is a bar test"

To delete all words ending with a letter ‘g’ in each line using gnu/awk, enter:

awk '{gsub("[a-zA-Z0-9]*[g|G]$", "");print}' input

Or

awk '{gsub("\<[a-zA-Z0-9]*[g|G]\>", "");print}' input

Posted by: SXI ADMIN

The author is the creator of SXI LLC and a seasoned sysadmin, DevOps engineer, and a trainer for the Linux operating system/Unix shell scripting. Get the latest tutorials on SysAdmin, Linux/Unix and open source topics via RSS/XML feed or weekly email newsletter.